diffrence between char s[]="hello"; or char *s ="hello"

	/*
	HIOS@Study material
	Topic :: Different between
	1: char s[]=" hios technology ";
	2: char *s=" hios technology " ;
	*/
	#include <iostream>
	using namespace std;
	char *getString1()
	{
	char str[] = "you love me ?";
	return str;
	}
	char *getSring2()
	{
	char *str="i love you !";
	return str;
	}
	int main()
	{
	cout<<getSring2();
	cout<<endl;
	cout<<getString1()<<endl;
	}
	/* out put
	i love you
	Some garbage value
	*/
	#Explanation
	char * allocates a pointer, while char [] allocates an array. Where does the string go in the former case, you ask? The compiler secretly allocates a static anonymous array to hold the string literal.
	char *x = "Foo";
	// is approximately equivalent to:
	static const char __secret_anonymous_array[] = "Foo";
	Note that you must not ever attempt to modify the contents of this anonymous array via this pointer; the effects are undefined (often meaning a crash):
	x[1] = 'O'; // BAD. DON'T DO THIS.
	Using the array syntax directly allocates it into new memory. Thus modification is safe:
	char x[] = "Foo";
	x[1] = 'O'; // No problem.
	However the array only lives as long as its contaning scope, so if you do this in a function, don't return or leak a pointer to this array - make a copy instead with strdup() or similar. If the array is allocated in global scope, of course, no problem.
	char s[]="string" // initialised in data segment
	char *s="string " // initialised in "text" segment of the program
	//source#stackoverflow.com

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